Application - mathematics

math wrote:Nah - I don't think anyone under the radar of Google would prove the answer this rigorously.

*lol* That's how I found the problem and it was actually explained almost identically to the solution you posted. I admittedly am horrible at calc and was lucky to have gotten through it alive. Not my strongest subject by a long shot and it never really clicked. Algebra, trig, etc...not a problem. Calc = my arch nemesis *lol*

Nah - I don't think anyone under the radar of Google would prove the answer this rigorously.

That is the correct answer...

Now my next question is did you google it? *lol*

First, the anti-derivative g(x) exists since (1) f(x) = 4x + 3 is well defined since there's a bijection between its domain and co-domain and (2) f(x) is continuous in the set of all real numbers since every real number in domain the limit exists since f(x) is a polynomial and the limit is equal to the corresponding real number in co-domain.

Next, we see that g(x) = 2x^2 + 3x + C by elementary integral calculus, for some constant C. Since g(6) = 6, solving for C, we find that C = -84. Then we see that g(3) is -57

OK...what's the answer to this?

Given f (x) = 4x + 3 and g (x) be the anti derivative of f (x). Then the value of g (6) is 6 and finds the value of g (3).

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